0.5x^2-4=14

Solution for 0.5x^2-4=14 equation:

0.5x^2-4=14

We move all terms to the left:

0.5x^2-4-(14)=0

We add all the numbers together, and all the variables

0.5x^2-18=0

a = 0.5; b = 0; c = -18;
Δ = b2-4ac
Δ = 02-4·0.5·(-18)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6}{2*0.5}=\frac{-6}{1}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6}{2*0.5}=\frac{6}{1}
=6
$